在线一元二次方程计算器实例

来源:您讯学院 作者: 时间:2015-11-14 06:46:05
在线一元二次方程计算器实例
点评:在线一元二次方程式计算器实例分享,有需要的朋友可以参考一下,希望对大家有所帮助!
复制代码 代码如下:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html" charset="utf-8">
<title>在线一元二次方程式计算器</title>
</head>
<body>
<form name="fquad">
    <p align="center">解二次方程式计算<br>
     </p>
    <table align="center">
        <tbody>
            <tr>
                <td bgcolor="#990000">
                <h2><font color="#ffffff"><input size="4" name="fa" type="text"> x<sup>2</sup>+ <input size="4" name="fb" type="text"> x + <input size="4" name="fc" type="text"> = 0 <input onclick="checkQuad()" type="button" value="解题"> <input type="reset" value="重置"> </font></h2>
                <p align="center"><font color="#ffffff"><b>一元二次方程的解法</b></font></p>
                </td>
            </tr>
            <tr>
                <td bgcolor="#990000">
                <h2><font color="#ffffff">x<sub><a style="text-decoration: none" ><font color="#ffffff">1</font></a></sub>=<input size="45" name="x1" type="text"> <br>
                x<sub>2</sub>=<input size="45" name="x2" type="text"> </font></h2>
                </td>
            </tr>
            <tr>
            </tr>
        </tbody>
    </table>
</form>
<p align="center">Made by CRoot</p>
<script language="JavaScript">
<!-- 
var rootparti;
var rootpart;
var det;
var rootparti1;
var rootparti2;
var a;
var b;
var c;
var x1;
var x2;
var i = "i";
function checkQuad() {
var a = document.fquad.fa.value;
var b = document.fquad.fb.value;
var c = document.fquad.fc.value;
if (a == 0 && c != 0) {
x1 = -c / b;
x2 = "Not a quadratic equation, but here is your answer for x";
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
else if (a == "" && c != 0) {
x1 = -c / b;
x2 = "Not a quadratic equation";
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
else {
quad();
   }
}
function quad() {
var a = document.fquad.fa.value;
var b = document.fquad.fb.value;
var c = document.fquad.fc.value;
det = Math.pow(b,2) - 4 * a * c;
rootpart = Math.sqrt(det) / (2 * a);
rootparti = (Math.sqrt(-det) / (2 * a)) + i;
if (parseFloat(rootparti) < 0) {
rootparti1 = rootparti;
rootparti2 = (-1 * parseFloat(rootparti)) + i;
}
else {
rootparti1 = (-1 * parseFloat(rootparti)) + i;
rootparti2 = rootparti;
}
if (rootparti1 == "1i") {
rootparti1 = i;
rootparti2 = "-i";
}
else if (rootparti1 == "-1i") {
rootparti1 = "-i";
rootparti2 = i;
}
if (det == 0) {
x1 = x2 = -b / (2 * a);
}
else if (det > 0) {
x1 = (-b + Math.sqrt(det)) / (2 * a);
x2 = (-b - Math.sqrt(det)) / (2 * a);
}
else if ((-b / (2 * a)) == 0) {
x1 = rootparti1;
x2 = rootparti2;
}
else {
x1 = (-b / (2 * a) + " + " + rootparti1);
x2 = (-b / (2 * a) + " + " + rootparti2);
}
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
// will solve for complex numbers
//   -->
</script>
</body>
</html>
 

 

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